如何获得laravel路由行为的名字吗？ 有大用

把动作的名称，你需要使用：

echo Route::getCurrentRoute()->getActionName();

而不是

echo Route::getActionName();

得到的路径动作名称中间件我做：

<?php
namespace App\Http\Middleware;

use Closure;
use Illuminate\Routing\Router;

class HasAccess {

    protected $router;

    public function __construct(User $user, Router $router)
    {
        $this->router = $router;
    }

    public function handle($request, Closure $next)
    {
        $action_name = $this->router->getRoutes()->match($request)->getActionName();
        //$action_name will have as value 'App\Http\Controllers\HomeController@showWelcome'
        //Now you can do what you want whit the action name 
        return $next($request);
    }
}

编辑：你会不会是这个中间件保护线路：（

相反

use Illuminate\Routing\Route;

使用此

use Illuminate\Support\Facades\Route;

如果你想获得航线的别名，您可以使用：

Route::getCurrentRoute()->getName()

把动作名称只有（无控制器的名称）：

list(, $action) = explode('@', Route::getCurrentRoute()->getActionName());

只有方法名称可以使用…

$request->route()->getActionMethod()

或一个门面…

Route::getActionMethod()

5.1使用用于laravel：

$route = new Illuminate\Routing\Route();
$route->getActionName(); // Returns App\Http\Controllers\MyController@myAction
$route->getAction(); // Array with full controller info

这类有用的方法很多。只是检查代码的更多细节。

在5.4只得到laravel动作名称

explode('@', Route::getCurrentRoute()->getActionName())[1]

找不到更好的办法，使用视图中的一行…

你可能用得到的控制器详细形式请求本身

$request->route()->getAction()

Using Laravel 5.1, you can use

\Request::route()->getName()

Found a way to find the current route name works for laravel v5 , v5.1.28 and v5.2.10

Namespace

use Illuminate\Support\Facades\Route;

and

$currentPath= Route::getFacadeRoot()->current()->uri();

For Laravel laravel v5.3 you can just use:

use Illuminate\Support\Facades\Route;

Route::currentRouteName();

If you need url, not route name, you do not need to use/require any other classes:

url()->current();

If you want to selected menu on multiple routes you may do like this:

<li class="{{ (Request::is('products/*') || Request::is('products') || Request::is('product/*') ? 'active' : '') }}"><a href="{{url('products')}}"><i class="fa fa-code-fork"></i>&nbsp; Products</a></li>

Or if you want to selected just single menu you may simply do like this:

<li class="{{ (Request::is('/users') ? 'active' : '') }}"><a href="{{url('/')}}"><i class="fa fa-envelope"></i>&nbsp; Users</a></li>

Also tested in Laravel 5.2

Hope this help someone.

You can use in template:

<?php $path = Route::getCurrentRoute()->getPath(); ?>
<?php if (starts_with($path, 'admin/')) echo "active"; ?>

Laravel 5.2 You can use

$request->route()->getName()

It will give you current route name.

Shortest way is Route facade \Route::current()->getName()

In a controller action, you could just do:

public function someAction(Request $request)
{
    $routeName = $request->route()->getName();
}

$request here is resolved by Laravel's service container.

getName() returns the route name for named routes only, null otherwise (but you could still explore the \Illuminate\Routing\Route object for something else of interest).

In other words, you should have your route defined like this to have "nameOfMyRoute" returned:

Route::get('my/some-action', [
    'as' => 'nameOfMyRoute',
    'uses' => 'MyController@someAction'
]);

Request::path(); is better, and remember to Use Request;

In 5.2, you can use the request directly with:

$request->route()->getName();

or via the helper method:

request()->route()->getName();

Output example:

"home.index"

Now in Laravel 5.3 I am seeing that can be made similarly you tried:

$route = Route::current();

$name = Route::currentRouteName();

$action = Route::currentRouteAction();

https://laravel.com/docs/5.3/routing#accessing-the-current-route

In a Helper file,

Your can use Route::current()->uri() to get current URL.

Hence, If you compare your route name to set active class on menu then it would be good if you use

Route::currentRouteName() to get the name of route and compare

I have used for getting route name in larvel 5.3

Request::path()