欢迎各位兄弟 发布技术文章
这里的技术是共享的
与 firstOrcreate 或 firstOrNew (它们是 laravel 内置的方法 )不同
firstOrcreate 或 firstOrNew 的参数是键值的数组 比如 TuiguangEffect::firstOrNew(['name' => 'Flight 10'])
15 2 | I have recently started working with Laravel and Eloquent, and was wondering about the lack of a find or create option for models. You could always write, for example: $user = User::find($id);if (!$user) {
$user = new User;}However, is there not a better way to find or create? It seems trivial in the example, but for more complex situations it would be really helpfully to either get an existing record and update it or create a new one. |
I am not an Eloquent expert, however even if there is no such method, most probably you can define it in an abstract class or trait that all of your models extend / make use of. – bagonyi Dec 1 '13 at 5:31 |
30 | Below is the original accepted answer for: laravel-4 There is already a method // Put this in any model and use// Modelname::findOrCreate($id);public static function findOrCreate($id){
$obj = static::find($id);
return $obj ?: new static;}From your controller, you can use $user = User::findOrCreate(5);$user->first_name = 'Jhon';$user->last_name = 'Doe';$user->save(); If a user with This is another way to do the same thing: public function scopeFindOrCreate($query, $id){
$obj = $query->find($id);
return $obj ?: new static;}Instead of creating a static method, you can use a $user = User::findOrCreate(5); Update:The In Laravel 5.3, the public function firstOrCreate(array $attributes, array $values = []) Which means you can use it like this: User::firstOrCreate(['email' => $email], ['name' => $name]); User's existence will be only checked via email, but when created, the new record will save both email and name. |
findOrCreate doesn't exist in Laravel 5x, as you cannot create something using only the ID. I think what you are referring to is findOrNew. – SteveEdson Mar 3 '16 at 11:15 Right @SteveEdson but it's firstOrCreate :-) – The Alpha Mar 3 '16 at 12:09 |
25 | Alternatively, in this case you can also use Laravel's function and search for id as an attribute, i.e. $user = User::firstOrCreate(['id' => $id]); |
Docs for 4: laravel.com/api/4.1/Illuminate/Database/Eloquent/… – everyman Sep 21 '15 at 10:26 Docs for 5: laravel.com/api/5.1/Illuminate/Database/Eloquent/… – everyman Sep 21 '15 at 10:27 |
10 | Laravel 4 models have a built-in $user = User::findOrNew($id); |
note find or new instantiates an object but you still need to use save() function – Gokigooooks Feb 25 '16 at 11:17 |
5 | In Laravel 5: // Retrieve the flight by the attributes, or create it if it doesn't exist...$flight = App\Flight::firstOrCreate(['name' => 'Flight 10']);// Retrieve the flight by the attributes, or instantiate a new instance...$flight = App\Flight::firstOrNew(['name' => 'Flight 10']); |
3 | Find or New based on primary key id $user = User::findOrNew($id); // if exist then update else insert$user->name= $data['full_name'];$user->save(); First or New based on non-primary key single filed // get the record where field_name=value else insert new record$user = User::firstOrNew(['field_name'=>'value']); $user->name= $data['full_name'];$user->save(); First or New based on non-primary key multiple filed // get the record where field_name1=value1 and field_name2=value2, else insert new record$user = User::firstOrNew(['field_name1'=>'value1','field_name2'=>'value2']);$user->name= $data['full_name'];$user->save(); |
2 | You can use firstOrCreate (It's working with Laravel 4.2) $bucketUser = BucketUser::firstOrCreate([ 'bucket_id' => '1', 'user_id' => '2',]); returns found instance or new instance. |
