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CI 如何ajax方式上传图片? 有大用

看了CI框架里的文件上传类 http://codeigniter.org.cn/user_guide/libraries/file_uploading.html

5个回答

3

依赖:http://malsup.com/jquery/form/
效果:

<div class="avatar-upload" id="avatar-upload">
    <form method="POST" action="url-here" accept-charset="UTF-8" id="upload" enctype="multipart/form-data">

   <a href="#" class="btn button-change-profile-picture">
    <label for="upload-profile-picture">
    <span id="upload-avatar">更换新头像</span>
    <input name="image" id="image" type="file" class="manual-file-chooser js-manual-file-chooser js-avatar-field">
    </label>
   </a>
    </form>
    <div class="span5">
        <div id="output" style="display:none">
        <img src="#">
        </div>
    </div>
</div>






<script type="text/javascript">
     $(document).ready(function() {
            var options = {
                beforeSubmit:  showRequest,
                success:       showResponse,
                dataType: 'json'
            };
            $('#image').on('change', function(){
                $('#upload-avatar').html('正在上传...');
                $('#upload').ajaxForm(options).submit();
            });
        });
        
     function showRequest() {
        $("#validation-errors").hide().empty();
        $("#output").css('display','none');
        return true;
    }
    
    function showResponse(response)  {
        if(response.success == false)
        {
            var responseErrors = response.errors;
            $.each(responseErrors, function(index, value)
            {
                if (value.length != 0)
                {
                    $("#validation-errors").append('<div class="alert alert-error"><strong>'+ value +'</strong><div>');
                }
            });
            $("#validation-errors").show();
        } else {
            $("#output img").attr('src',response.imageUrl);
            

            console.log(response.imageUrl);
        }
    }

</script>



服务器端实现的比如Ajax.php,你只要保证返回imageUrl这个json字段就可以了

0

前几天刚做完一个CI + AJAX 上传的项目,大概是用到Formdata的方法上传了
下面是代码
var fd = new FormData(); fd.append("userfile", 1); fd.append("userfile", $("#imgfile").get(0).files[0]); fd.append("uid",$('#class-author').val()); $.ajax({ url: "clazz/upload", type: "POST", processData: false, contentType: false, data:fd, success: function(d) { alert(d); window.photo_url = d; alert("上传成功"); }

亲测可用=。=希望可以帮助你~

来自  https://segmentfault.com/q/1010000002771445
普通分类: