How can I add a class to #markup output?

I'm using this code to add a cancel button to my form. The link is generated through #markup:

  $form['actions']['cancel'] = array(
    '#markup' => l(t('Cancel'), $destination),
    '#weight' => 20,
  );

I'd like to add a class, cancel, to the link. I tried adding this line:

'#attributes' => array('class' => array('cancel')),

but the class is not added. I'm guessing because #attributes cannot modify #markup? How can I add the class in this case?

正确答案 


 

1down voteaccepted

You can do this... $form['actions']['cancel'] = array( '#markup' => l(t('Cancel'), $destination, array('attributes' => array('class' => array('cancel')))), '#weight' => 20, ); The third argument on the 'link' function is for attributes and such... l($text, $path, array $options = array()) Documentation: http://api.drupal.org/api/drupal/includes%21common.inc/function/l/7 shareimprove this answer edited Jan 4 '13 at 1:41 Patrick Kenny 11.6k762169 answered Jan 3 '13 at 17:02 Alex Gill 3,0441917

This is great for that user's case, but would you know a way to make it more general on the form element itself, and not just the link generated? I'm asking because I have a similar issue, but would like to wrap the class around the entire element (#type => 'item') that's using #markup, but according to Drupal's FAPI page, #attributes isn't available for #item. – UnsettlingTrend Jul 15 '15 at 15:55 Have you tried using #prefix and #suffix? api.drupal.org/api/drupal/… – Alex Gill Jul 17 '15 at 10:00 Yeah, but I was trying to do it without having to add another div; I know, one more div is somewhat inconsequential, but I try to avoid the snowball effect...