Get current domain 当前域名 有大用

Using $_SERVER['HTTP_HOST'] gets me (subdomain.)maindomain.extension. Seems like the easiest solution to me.

Edit: if you're actually 'redirecting' through an iFrame you could add a get parameter which states the domain.

<iframe src="myserver.uk.com?domain=one.com"/>

And then you could set a session variable that persists this data throughout your application.

The best use would be

echo $_SERVER['HTTP_HOST'];

And can be used like this

if(strpos( $_SERVER['HTTP_HOST'], 'banana.com') !== false){
    echo "Yes this is indeed the banana.com domain";
}

This code below is a good way to see all the variables in $_SERVER in a structured HTML output with your keywords highlighted, that halts directly after execution. Since I do sometimes forget which one to use myself - i think this can be nifty.

<?php 
// change banana.com to the domain you were looking for.. 
$wordToHighlight= "banana.com";
$serverVarHighlighted = str_replace( $wordToHighlight, '<span style=\'background-color:#883399; color: #FFFFFF;\'>'. $wordToHighlight .'</span>',  $_SERVER );
echo "<pre>";
print_r( $serverVarHighlighted );
echo "</pre>";
exit();
?>

Try $_SERVER['SERVER_NAME']. Tips: Create a PHP file that calls the function phpinfo() and see the "PHP Variables" section. There is a bunch of useful variables we never thought there.

I know this might not be entirely on the subject, but in my experience, I find storing WWW-ness of current URL in a variable useful.

Edit: In addition, please see my comment below, to see what this is getting at.

This is important when determining whether to dispatch Ajax calls with "www", or without:

$.ajax("url" : "www.site.com/script.php", ...

$.ajax("url" : "site.com/script.php", ...

When dispatching an Ajax call the domain name must match that of in the browser's address bar, otherwise you will have Uncaught SecurityError in console.

So I came up with this solution to address the issue:

<?php
    substr($_SERVER['SERVER_NAME'], 0, 3) == "www" ? $WWW = true : $WWW = false;

    if ($WWW) {
        /* We have www.example.com */
    } else {
        /* We have example.com */
    }
?>

Then, based on whether $WWW is true, or false run the proper Ajax call.

I know this might sound trivial, but this is such a common problem that is easy to trip over.

Late answer, but here it goes:

$currentDomain = preg_replace('/www\./i', '', $_SERVER['SERVER_NAME']);

It will give you a clean domain name, without www